Random place to ask this....but I need help with an Algebra 2 question, if someone can help that'd be great....I have to find the real number solutions of this equation x^3-5x^2+8x-4=0
The answer depends if you're in University or high school.... For high school, you can just guess as alan_t mentioned. In university, it depends if they want you to just find the roots using a graphic calculator or actually solve it using like Cardano's method or Legrange's method. Wikipedia will shed some light...
The only thing I see to do is factor out an (x - 1), which you can do by either long dividing into it or synthetically divide. Either way, you're gonna get (x - 2)^2. So it turns into [(x-2)^2][x-1] = 0 So x = 1, x = 2. Reallyyy small integers --- Edit: After posting, I realise that exactly what I said might sound confusing depending on what you've actually been taught in class. xD I'm too tired to think of the explanation; I only see the answer. Yay for being a math major x_x
That's kind of cheating isn't it? It's like figuring out the roots and then just factoring it out of the cubic equation But I guess again, it depends what level he is at. But looking at the equation and at the roots, I suppose it was not meant to be difficult...